Question

If the passenger is 3.2m above her friend when the camera is tossed, what is the minimum initial speed of the camera, if it is to just reach the passenger? (Hint: When the camera is thrown with its minimum speed, its speed on reaching the passenger is the same as the speed of the passenger.)

Answer 1

The minimum velocity required is 7.923 m/s

Step-by-step explanation:

The minimum speed required shall be equal to the speed that allows the camera to just reach a height of 3.2 meters

This can be solved using the third equation of kinematics as

`v^(2)=u^(2)+2gs`

where

v = final speed of object

u = initial speed of object

s = is the height attained

Since finally velocity becomes zero thus the above equation reduces to

`0=u^(2)-2* 9.81* 3.2\\\\\therefore u=√(2* 9.81* 3.2)\\\\u=7.923m/s`