Question

What would be the pressure (in atmospheres) exerted by 0.75 moles of an ideal gas, if the gas filled a 40.5 liter container at a temperature of 19 degrees Celsius? (The ideal gas constant is 0.0821 L•atm/mol•K.)

Answer 1

P = 0.44 atm

Step-by-step explanation:

given data:

gas constant R = 0.0821 L.atm/mol. k

Temperature = 19 degree celcius = 19+273 = 292 K

Volume = 40.5 L

FROM IDEAL GAS EQUATION IS WE HAVE

mole n = 0.75

`P = (nRT)/(V)`

putting all value to get the desired value to get desired pressure value.

`= ((0.75)*( 0.0821)*(292))/((40.5 L))`

P = 0.44 atm