Answer:
968.75 mL of blood serum are needed to obtain 3.1 g of Na⁺
885.71 mL of blood serum are needed to obtain 3.1 g of Cl⁻
Step-by-step explanation:
Knowing that the blood serum contains 3.2 mg/mL of sodium ions (Na⁺) we devise the following reasoning:
if 3.2 mg of sodium ions are found in 1 mL of blood serum
then 3100 mg of sodium ions are found in X mL of blood serum
X = (1 × 3100) / 3.2 = 968.75 mL
Knowing that the blood serum contains 3.5 mg/mL of chlorine ions (Cl⁻) we devise the following reasoning:
if 3.5 mg of chlorine ions are found in 1 mL of blood serum
then 3100 mg of chlorine ions are found in X mL of blood serum
X = (1 × 3100) / 3.5 = 885.71 mL