Question

A motorboat accelerates uniformly from a ve- locity of 7.0 m/s to the west to a velocity of 2.4 m/s to the west. If its acceleration was 2.7 m/s2 to the east, how far did it travel during the acceleration? Answer in units of m.

Answer 1

Answer:Until a train is a safe distance from the station it must travel at 5 m/s. Once the train is on open track it can speed up to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train? (Round your answer to the nearest whole number

Explanation:Until a train is a safe distance from the station it must travel at 5 m/s. Once the train is on open track it can speed up to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train? (Round your answer to the nearest whole number

Answer 2

Distance, d = 8 meters

Step-by-step explanation:

Given that,

Initial velocity of the motorboat, u = 7 m/s (west)

Final velocity of the motorboat, v = 2.4 m/s (west)

Acceleration of the motorboat,
`a=-2.7\ m/s^2` (east)

We need to find the distance covered by it. It can be calculated as :

`v^2-u^2=2as`

`(2.4)^2-(7)^2=2* (-2.7)s`

s = 8 meters

So, the distance covered by the motor boat is 8 meters. Hence, this is the required solution.