Answer:
The time the train blocked the crossway is
0.007934h=0.476 min=28.6 s
Step-by-step explanation:
The average speed is given by
V= (Vi+Vf)/2
and
V= dx/dt
Where
Vi= initial speed
Vf= final speed
dx= change of position=0.384 km
dt=time the train blocked the crossway
dt=2dx/(Vi+Vf)
dt=2*0.384 km/(77.3 +19.5) km/h
dt=0.007934h
dt=0.007934h*(60min/1h)=0.476 min
dt=0.476 min*(60s/1min)=28.6 s