Final answer:
To determine the number of general admission and student tickets sold, we can use a system of equations. The solution is 114 general admission tickets and 246 student tickets.
Step-by-step explanation:
To solve this problem, we can use a system of equations. Let's assume that x represents the number of general admission tickets sold and y represents the number of student tickets sold.
We know that the total number of tickets sold is 360, so we can write the equation x + y = 360.
We also know that the total amount of money collected from ticket sales is $4,170. Since general admission tickets cost $15 and student tickets cost $10, we can write the equation 15x + 10y = 4170.
To solve this system of equations, you can use substitution or elimination. I will use elimination in this example.
Multiply both sides of the first equation by 10 to make the coefficients of y the same in both equations: 10x + 10y = 3600.
Subtract the second equation from the first equation to eliminate y: (15x + 10y) - (10x + 10y) = 4170 - 3600, which simplifies to 5x = 570.
Divide both sides of the equation by 5 to solve for x: x = 570/5 = 114.
- Substitute the value of x back into the first equation to solve for y: 114 + y = 360. Subtract 114 from both sides of the equation to find that y = 246.
Therefore, 114 general admission tickets and 246 student tickets were sold.