Answer:
a.
Input limit:

Budget limit:

b.
L=20
K=80
Step-by-step explanation:
Ok, you save me a little bit of work and resolved the point a.
Indeed, the equations for Input limit and Budget limit are the ones you put in the question.
Now I will show you how to find the quantities of the two inputs in order to have a maximum output taking into account the input limit and the budget limit:
First, we need to put our equations in function of one of the variables, lets do it with L (Labor):
Input limit:


Budget Limit:



Now we match the 2 equations and find the value of K
L=L





Now that we have the optimum K we replace in any of the two equations to find the optimum L

And then we replace in the Input limit and Budget limit equations to verify:
Input limit:

Budget Limit:
