Answer:
The width of the walkway is 4 feet.
Explanation:
The garden and a walkway around its perimeter have an area of 460 square feet.
The length of the garden = 15 feet
The width of the garden = 12 feet
Assuming that walkway is of uniform width, we can solve the following equation.
![(12+2x)*(15+2x)= 460](https://img.qammunity.org/2020/formulas/mathematics/high-school/a2gchaxu52aqzr0zkcakksupkrjxynj252.png)
Expanding this we get;
![4x^(2)+54x+180=460](https://img.qammunity.org/2020/formulas/mathematics/high-school/tc1hpnuon9klg0gjrqhrb1x1u74k4xuitx.png)
![=> 4x^(2)+54x-280=0](https://img.qammunity.org/2020/formulas/mathematics/high-school/yybizw301ok809a4nvj92zd2rp45q6yce6.png)
We will solve this using quadratic equation formula:
![x=\frac{-b\pm \sqrt{b^(2) -4ac} }{2a}](https://img.qammunity.org/2020/formulas/mathematics/high-school/xmomwzcjagbafqjo3crj9e5haslm04l6y0.png)
Here a = 4 , b = 54 , c = -280
We get the roots as x = 4 and x =
![-(35)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/36hffvy0ik72wcmd3yhx0e5nwf9x0pyqh5.png)
Neglecting the negative value, we will take x = 4 feet.
Hence, the width of the walkway is 4 feet.