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Determine the angle for the first order maximum of a 12,000 lines/cm diffraction grating and light wavelength at 550 nm

1 Answer

1 vote

Answer:


\theta=41.29^(\circ)

Step-by-step explanation:

Given that,

Number of lines,
N=12000\ lines/cm


N=12000* 10^2\ lines/m

Wavelength,
\lambda=550\ nm=550* 10^(-9)\ m

We need to find the angle for the first order maximum, n = 1


d=(1)/(N)


d=(1)/(12000* 10^2)


d=8.33* 10^(-7)\ m

Using the grating equation as :


d\ sin\theta=n\lambda


sin\theta=(\lambda)/(d)


sin\theta=(550* 10^(-9))/(8.33* 10^(-7))


\theta=41.29^(\circ)

So, the angle for the first order maximum is 41.29 degrees. Hence, this is the required solution.

User Stieffers
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