Question

2y = x + 3

5y = x - 7
7
What is the solution set of the given system?
{f-13.-4/3}}
{(1/3,4/3)
{l-29/3.-10/3}}
{(29/3, 10/3)

Answer 1

For this case we must solve the following system of equations:

`2y = x + 3\\5y = x-7`

We clear "x" from the second equation:

`x = 5y + 7`

We substitute in the first equation:

`2y = 5y + 7 + 3\\2y = 5y + 10\\2y-5y = 10\\-3y = 10\\y = - \frac {10} {3}`

We look for the value of the variable "x":

`x = 5 (- \frac {10} {3}) + 7\\x = - \frac {50} {3} +7\\x = - \frac {29} {3}`

Thus, the solution of the system is given by:

`(- \frac {29} {3}, - \frac {10} {3})`

Answer:

`(- \frac {29} {3}, - \frac {10} {3})`

Answer 2

Solution: { -29/3 , -10/3 }

Explanation:

2y = x + 3 ---------> equ 1

5y = x - 7 equ 2

equ 1 - equ s ====> -3y = 10

y = -10/3

Put y = -10/3 in equ 1

2 * (-10/3) = x + 3

-20/3 = x + 3

(-20/3) - 3 = x

(-20/3) - (9/3) = x

(-20 - 9) / 3 =x

x = -29/3

Solution: { -29/3 , -10/3 }