Question

A given line has the equation 10x+2y=-2.

What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0,
12)?
O y=-5x+12
5x+y=12
Oy-12=5(x-0)
5x+y=-1

Answer 1

It's A, y=5x+12. Hope I helped!!

Answer 2

The equation of a line of the slope-intersection form is given by:

`y = mx + b`

Where:

m: It's the slope

b: It is the cut-off point with the y axis

If two lines are parallel then their slopes are equal.

We have the following line:

`10x + 2y = -2\\2y = -10x-2\\y = -5x-1`

Thus, the slope of the line is -5.

Therefore a parallel line is of the form:

`y = -5x + b`

We replace the point
`(0,12)`

`12 = -5 (0) + b\\12 = b`

Finally, the equation is of the form:

`y = -5x + 12`

Answer:

`5x + y = 12`