Question

A person hears sound wave beast at 3000Hz at the temperature of 30 °C. What is the person's ear canal length? Please explain

Answer 1

The person's ear canal length is 2.91 cm.

Step-by-step explanation:

Given that,

Frequency = 3000 Hz

Temperature = 30°C

We need to calculate the speed

Using equation of sound wave with temperature

[texs]v(t)=331+0.6\times T[/tex]

Put the value of T

`v(t)=331+0.6*30^(\circ)\ C`

`v(t)=349\ m/s`

We need to calculate the length

Using formula of closed organ pipe

`f=(v)/(4L)`

`L=(v)/(4f)`

Where, L = length

v = velocity

f = frequency

Put the value into the formula

`L=(349)/(4*3000)`

`L=0.0291\ m`

`L=2.91*10^(-2)\ m`

`L=2.91\ cm`

Hence, The person's ear canal length is 2.91 cm.