Question

You have 846 ml of 3.95 M HCl. Using a volumetric pipet, you take 268 ml of that solution and dilute it to 803 ml in a volumetric flask. Next, you take 100.00 ml of that solution and dilute it to 184 ml in a volumetric flask. What is the concentration of hydrochloric acid in the final solution?

Answer 1

Answer: The concentration of hydrochloric acid in the final solution is 0.72 M

Step-by-step explanation:

According to the dilution law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of stock solution = 3.95 M

`V_1` = volume of stock solution = 268 ml

`M_2` = molarity of diluted solution = ?

`V_2` = volume of diluted solution = 803 ml

`3.95* 268=M_2* 803`

`M_2=1.32M`

Next, you take 100.00 ml of that solution and dilute it to 184 ml in a volumetric flask.

According to the dilution law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of stock solution = 1.32 M

`V_1` = volume of stock solution = 100 ml

`M_2` = molarity of diluted solution = ?

`V_2` = volume of diluted solution = 184 ml

`1.32* 100=M_2* 184`

`M_2=0.72M`

Thus concentration of hydrochloric acid in the final solution is 0.72 M