Question

If 133mL of a 1.2 M glucose solution is diluted to 41.0L, what is the molarity of the diluted solution?

Answer 1

the formula we is as follows:-

M1V1= M2V2

where

M1=1.2

V1=0.133l

V2=41l

M2=?

1.2 × 0.133 = 41 × M2

0.1596 = 41 × M2

M2 = 0.15960/41

M2 = 0.0038926829