Evaluate the expression for the given values: 2x^2 _8xy+3y^2 for x = -3 and y = 2

asked Jan 14, 2020 5.5k views

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Answer:

Value = 78

Explanation:

We replace the values, x = -3 and y = 2, so:

$2x^(2) -8xy+3y^(2) =2(-3)^(2)-8(-3)(2)+3*2^(2)=2*9+48+3*4=18+48+12=78\\$

Non Sequitor answered Jan 20, 2020

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