Question

Carl Lewis set a world record for the 100.0-m run with a time of 9.86 s. If, after reaching the finish line, Mr. Lewis walked directly back to his starting point in 90.9 s, what is the magnitude of his average velocity for the 200.0 m?

Answer 1

The magnitude of his average velocity for the 200.0 m is zero.

Step-by-step explanation:

Given that,

Distance = 100.0 m

Time = 9.86 s

Now, back to his starting point

Time = 90.9 s

Average velocity :

Average velocity is equal to the total displacement divided by the total time.

In mathematical form,

`v_(avg)=(D)/(T)`

Where, D = Displacement

t = time

He started at the Start line, and ended at the Start Line.. his Net displacement will be Zero so the average velocity will be

Using formula of average velocity,

`v_(avg)=(100-100)/(90.9-9.86)`

`v_(avg)=0`

Hence, The magnitude of his average velocity for the 200.0 m is zero.