Question

Quadratic Formula and the two solutions I would get

Answer 1

A quadratic equation is given by three parameters:

`ax^2+bx+c=0`

• a is the quadratic coefficient, since it multiplies
  `x^2`
• b is the linear coefficient, since it multiplies
  `x`
• c is the numeric coefficient, since it's a pure number.

The quadratic formula states that the two (possible) solutions for a quadratic equation are

`ax^2+bx+c=0 \iff x_(1,2) = (-b\pm√(b^2-4ac))/(2a)`

In your case, you have

`a=8,\quad b=-10,\quad c=-1`

So, your quadratic equation and its solving formula become

`8x^2-10x-1=0 \iff x_(1,2) = (10\pm√(100+32))/(16)=(10\pm√(132))/(16)`