Question

A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of 11.0 m/s. How long does he have to get out of the way? (**Note** Assume that the shot returns back to its original height)

Answer 1

Time= 2,24 seconds

Step-by-step explanation:

In the vertical movement you have an accelerated movement where the acceleration is gravity.

You have to use the equation

`v=vo-gt\\\\v= final velocity (0 m/s)\\\\vo= Initial velocity (11 m/s)\\\\g= gravity (9.8 m/s^(2) )`

t= 1,122 ( this will be the rise time)

To know the total time you must multiply 2, because you have to ssume that the shot returns back to its original height

total time= 2*1,122= 2,244 seconds