Answer : The heat energy needed would be, 6486.5125 J
Explanation :
To calculate the change in temperature, we use the equation:
![q=mc\Delta T\\\\q=mc(T_2-T_1)](https://img.qammunity.org/2020/formulas/chemistry/college/qbq5ucbtrwuunc4ly7j77ojk5vik52kaci.png)
where,
q = heat needed = ?
m = mass of aluminum = 223 g
c = specific heat capacity of aluminum =
![0.895J/g^oC](https://img.qammunity.org/2020/formulas/chemistry/college/5mlpxh2vlhoqj6ixnd46fzgfhbijps518t.png)
= change in temperature
= initial temperature =
![22.5^oC](https://img.qammunity.org/2020/formulas/chemistry/college/2dfuc7gc73fcthoah3j7ejm8rnma8qxb4h.png)
= final temperature =
![55.0^oC](https://img.qammunity.org/2020/formulas/chemistry/college/xeds77tm7yluv29vz29oz4ymnxy1xbkkue.png)
Putting values in above equation, we get:
![q=223g* 0.895J/g^oC* (55.0-22.5)^oC](https://img.qammunity.org/2020/formulas/chemistry/college/hg78vvz718fub3u7sy5jtbgx4zexsrgwg4.png)
![q=6486.5125J](https://img.qammunity.org/2020/formulas/chemistry/college/2tnne0bp9devy8pzwzwbsso70rxc8enqug.png)
Therefore, the heat energy needed would be, 6486.5125 J