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How much heat energy would be needed to raise the temperature of a 223 g sample of aluminum [(C=0.895 Jig Cy from 22.5°C to 55 0°C? Η Ο Ο Ο ΟΟ 10x10) not enough information given Prov 40 25 11 Next >

1 Answer

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Answer : The heat energy needed would be, 6486.5125 J

Explanation :

To calculate the change in temperature, we use the equation:


q=mc\Delta T\\\\q=mc(T_2-T_1)

where,

q = heat needed = ?

m = mass of aluminum = 223 g

c = specific heat capacity of aluminum =
0.895J/g^oC


\Delta T = change in temperature


T_1 = initial temperature =
22.5^oC


T_2 = final temperature =
55.0^oC

Putting values in above equation, we get:


q=223g* 0.895J/g^oC* (55.0-22.5)^oC


q=6486.5125J

Therefore, the heat energy needed would be, 6486.5125 J

User Dave Moten
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