Question

A gas sample is heated from -20.0°C to 57.0°C and the volume is increased from 2.00 L to 4.50 L. If the initial pressure is 0.140 atm, what is the final pressure? Select one: a. 0.0477 atm b. –0.177 atm c. 0.411 atm d. 0.242 atm e. 0.0811 atm

Answer 1

The answer is e.

Step-by-step explanation:

We take:

`T_(1)=253K`

`V_(1)=2.00 l`

`P_(1)=0.14atm`

`V_(2)=4.50 l`

`T_(2)=330K`

Taking the gas as an ideal gas, we can use the ideal gas law:

`(PV)/(nRT)`

⇒
`n=(P_(1)V_(1))/(RT_(1))` ⇒
`n=0.013mol`

Then:

`P_(2)=(nRT_(2))/(V_(2))` ⇒
`P_(2)=0.0811 atm`

Taking R=0.08205atmL/molK.