Question

11,13,15,17 I need help with

Answer 1

Explanation:

[ Refer to the attached file ]

( Slide to refer all files )

________________________________

• To solve Questions of type 11 we need to simplify the equation by using mathematical operations !!

• To solve Questions of type ( 13 , 15 and 17 ) we try to make the bar numeral to come other side of decimal

° and by subtracting we get the required fraction !!

Answer 2

Answer: 11) x = 1 13)
`\bold{11)\quad x=1\qquad 13)\quad (4)/(9)\qquad 15)\quad (7)/(45)\qquad 17)\quad (5)/(12)}`

Explanation:

11) Multiply everything by the LCD to clear the denominator, then distribute the negative sign.

`(2(2x+1))/(5)-(x+2)/(3)=(1)/(5)\\\\\\(15)(2(2x+1))/(5)-(15)(x+2)/(3)=(15)(1)/(5)\\\\\\3\cdot2(2x+1)-5(x+2)=3(1)\\\\\\6(2x+1)-5(x+2)=3(1)\\\\12x + 6 - (5x + 10) = 3\\\\12x + 6 - 5x - 10 = 3\\\\7x-4=3\\\\7x=7\\\\\large\boxed{x=1}`

13) Since the repeating digit is in the tenths place, divide the repeating decimal by 9

`0.\overline4\quad =(4)/(9)`

15) Since the repeating digit is in the hundredths place, divide the repeating decimal by 90 and divide the non-repeating decimal by 10

`0.1\overline5\quad =(1)/(10)+(5)/(90)\\\\\\.\quad \quad =\bigg((9)/(9)\bigg)(1)/(10)+(5)/(90)\\\\\\.\quad \quad =(9)/(90)+(5)/(90)\\\\\\.\quad \quad =(14)/(90)\qquad \text{simplify by dividing by 2}\\\\.\quad \quad =\large\boxed{(7)/(45)}`

17) Since the repeating digit is in the thousandths place, divide the repeating decimal by 900 and the non-repeating decimal by 100

`0.41\overline6\quad =(41)/(100)+(6)/(900)\\\\\\.\quad \quad =\bigg((9)/(9)\bigg)(41)/(100)+(6)/(900)\\\\\\.\quad \quad =(369)/(900)+(6)/(900)\\\\\\.\quad \quad =(375)/(900)\qquad \text{simplify by dividing by 75}\\\\\\.\quad \quad =\large\boxed{(5)/(12)}`