Answer:
Each yard is 150 meters wide and 200 meters tall.
The overall area is 300 meters wide by 200 meters tall.
Explanation:
Let's say each yard has a width w and a height h. And let's say the part of the fence that divides them is parallel to the height. The total amount of fencing is therefore:
1200 = 4w + 3h
The total enclosed area is:
A = 2wh
Start by solving for w in the first equation:
1200 − 3h = 4w
w = 300 − 0.75h
Substitute into the second equation:
A = 2 (300 − 0.75h) h
A = 600h − 1.5h²
Take derivative and set to 0:
dA/dh = 600 − 3h
0 = 600 − 3h
h = 200
Solve for w:
w = 300 − 0.75h
w = 150
So each yard is 150 meters wide and 200 meters tall.
The overall area is 300 meters wide by 200 meters tall.