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Consider two planets with uniform mass distributions. The mass density and the radius of planet 1 are rho1 and R1, respectively, and those of planet 2 are rho2 and R2. What is the ratio of their masses?

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Answer:


(R_1^3 * \rho _1)/(R_2^3 * \rho _2)

Step-by-step explanation:

The mass density of an object with uniform mass distribution its defined as


\rho = (mass)/(volume).

So, if we know the volume, and, we can obtain the mass of the object:


mass = volume * \rho.

Now, we can take the planets as spheres, of course, this is only an approximation, but good enough for us. The volume of a sphere of radius r its:


Volume_(sphere) = (4)/(3) \pi r^3

So, for our planets, the mass its given by:


mass = volume * \rho\\mass = (4)/(3) \pi r ^3 \rho,

so


mass_(planet1) = (4)/(3) \pi R_1^3 \rho_1


mass_(planet2) = (4)/(3) \pi R_2^3 \rho_2

Now, we can take the ratio:


(mass_(planet1))/(mass_(planet2)) = ( (4)/(3) \pi R_1 ^3 \rho_1 )/( (4)/(3) \pi R_2 ^3 \rho_2 )

Now, we can just cancel the
(4)/(3) \pi [\tex] that appear in both sides of our fractions, and finally obtain: </p><p>[tex](R_1^3 * \rho _1)/(R_2^3 * \rho _2).

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