Question

A small glass bead has been charged to +20 nC. A small metal ball bearing 1.0 cm above the bead feels a 0.018 N downward electric force. What is the charge on the ball bearing?

Answer 1

The charge on the ball bearing is 6 x 10^-8 C.

Step-by-step explanation:

The charge on the ball bearing can be calculated using the formula:

F = qE

Where F is the electric force, q is the charge, and E is the electric field strength.

Given F = 0.018 N and E = 3.00 x 10^5 N/C, we can rearrange the formula to solve for q:

q = F/E

q = 0.018 N / 3.00 x 10^5 N/C = 6 x 10^-8 C

Therefore, the charge on the ball bearing is 6 x 10^-8 C.

Answer 2

`q=1*10^(-8)C`

Step-by-step explanation:

Let the charge on the ball bearing is q.

charge on glass bead, Q = 20 nC = 20 x 10^-9 C

Force between them, F = 0.018 N

Distance between them, d = 1 cm = 0.01 m

By use of Coulomb's law in electrostatics

`F=(KQq)/(d^(2))`

By substituting the values

`0.018=(9*10^(9)*20*10^(-9)q)/(0.01^(2))`

`q=1*10^(-8)C`

Thus, the charge on the ball bearing is
`q=1*10^(-8)C`