Question

h(t) = - 16t2 + 64t + 112 where t is the time in seconds. After how many seconds does the arrow reach it maximum height? Round to the nearest tenth of a second if necessary. The arrow reaches its maximum height in seconds.

Answer 1

2 seconds

Step-by-step explanation:

The function of height is given in form of time. For maximum height, we need to use the concept of maxima and minima of differentiation.

`h(t)=-16t^(2)+64t+112`

Differentiate with respect to t on both the sides, we get

`(dh)/(dt)=-32t+64`

For maxima and minima, put the value of dh / dt is equal to zero. we get

- 32 t + 64 = 0

t = 2 second

Thus, the arrow reaches at maximum height after 2 seconds.