Answer:
Part a)
T = 0.52 s
Part b)
![f = 1.92 Hz](https://img.qammunity.org/2020/formulas/physics/high-school/p6fq30xh883zwh8ho1e6unn3hixuuycxfg.png)
Part c)
![speed = 3.65 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/w2wrkdflfkat4xlldatzbzbb9unv6h3qpq.png)
Step-by-step explanation:
As we know that the particle move from its maximum displacement to its mean position in t = 0.13 s
so total time period of the particle is given as
![T = 4* 0.13 = 0.52 s](https://img.qammunity.org/2020/formulas/physics/high-school/2juq2g5cz4halpn4hvhrn1bmownvkawy30.png)
now we have
Part a)
T = time to complete one oscillation
so here it will move to and fro for one complete oscillation
so T = 0.52 s
Part b)
As we know that frequency and time period related to each other as
![f = (1)/(T)](https://img.qammunity.org/2020/formulas/physics/middle-school/nuagmqu2heg7dt383u3wyv31j18nizuyfe.png)
![f = (1)/(0.52)](https://img.qammunity.org/2020/formulas/physics/high-school/in6t71hhf7z4n1xk8uidt1q53pet2okcaz.png)
![f = 1.92 Hz](https://img.qammunity.org/2020/formulas/physics/high-school/p6fq30xh883zwh8ho1e6unn3hixuuycxfg.png)
Part c)
As we know that
wavelength = 1.9 m
frequency = 1.92 Hz
so wave speed is given as
![speed = wavelength * frequency](https://img.qammunity.org/2020/formulas/physics/high-school/dip1byo4ky15h0rtvpou679fqtiuyxqx40.png)
![speed = 1.92 * 1.9](https://img.qammunity.org/2020/formulas/physics/high-school/xfh3jw7cpzlh6cfpjo5d4urjcqc8m1j6ck.png)
![speed = 3.65 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/w2wrkdflfkat4xlldatzbzbb9unv6h3qpq.png)