Question

A rectangular painting measures 11inches by 17inches and contains a frame of uniform width around the four edges. The perimeter of the rectangle formed by the painting and its frame is 88inches. Determine the width of the frame.

Answer 1

4 in

Explanation:

The sum of length and width of the painting is 28 inches. The sum of length and width of the framed painting is 44 inches (half the perimeter). The difference of these sums is 16 inches, which is 4 times the width of the frame.

The width of the frame is (16 in)/4 = 4 in.

_____

Each edge of the framed painting measures ...

(frame width) + (painting width) + (frame width)

so the measure of two adjacent edges includes 4 times the frame width.