Question

A student solving a physics problem for the range of a projectile has obtained the expression

R= (v0^2)sin(2θ)/g
where v0=37.2meter/second, θ=14.1∘, and g=9.80 meter/second2. Use your calculator to evaluate R.

(A) 66.7 m
(B) 69.5 m
(C) 10.5 m
(D) 31.5 m

Answer 1

The range of the projectile is 66.7 meters.

Step-by-step explanation:

The range of a projectile is given by the following expression as :

`R=(v_o^2\ sin2\theta)/(g)`..............(1)

`v_o=37.2\ m/s`

`\theta=14.1^(\circ)`

`g=9.8\ m/s^2`

The range can be calculated using equation (1). Putting the values of all parameters we get :

`R=((37.2)^2\ sin2(14.1))/(9.8)`

R = 66.7 meters

So, the range of the projectile is 66.7 meters. Hence, this is the required solution.