Question

An object is dropped from a height H above the ground. This free-falling object requires 1.02 s to travel the last 39 m before hitting the ground. From what height H above the ground did the object fall?

Answer 1

H = 95.3 m

Step-by-step explanation:

Let the height from which object fall down is H

so the total time to fall is given as

`H = (1)/(2)gt^2`

now it cover 39 m in last 1.02 s of its path

`H - 39 = (1)/(2)g(t - 1.02)^2`

so now we have

`(1)/(2)gt^2 - 39 = (1)/(2)g(t - 1.02)^2`

by solving above equation

`t = 4.41 s`

Now the total height is given as

`H = (1)/(2)gt^2`

`H = (1)/(2)g(4.41)^2`

H = 95.3 m