Question

Which is the equation of a line with a slope of -1/3 and a Y intercept at (0,1)

Answer 1

y = -1/3x + 1

Explanation:

substitute the given values in y = mx + b where m is the slope and b is the y-intercept

y = -1/3x + b

at point (0, 1)

1 = -1/3 × 0 + b

1 = 0 + b

b = 1

y = -1/3 + 1

Answer 2

Answer: The required equation of the line is
`x+3y=3.`

Step-by-step explanation: We are given to find the equation of a line with slope
`-(1)/(3)` and y-intercept (0, 1).

We know that

the equation of a line with slope m and y-intercept (0, c) is given by

`y=mx+c~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)`

From the given information, we have

`\textup{slope, }m=-(1)/(3),\\\\\textup{y-intercept, }(0,c)=(0,1)~~~\Rightarrow c=1.`

Therefore, from equation (i), we get

`y=mx+c\\\\\Rightarrow y=-(1)/(3)x+1\\\\\Rightarrow 3y=-x+3\\\\\Rightarrow x+3y=3.`

Thus, the required equation of the line is
`x+3y=3.`