Answer:
The least number of tokens that Narcisse could have given to Aristide are: 3
Explanation:
Narcisse gives an "X" amount of the 7 tokens he initially had to aristide, which are added up to the 3 tokens that Aristide had. After that transaction the ratio changes from 7: 3 to 6: 5
![(7-X)/(3+X)=(5)/(6)](https://img.qammunity.org/2020/formulas/mathematics/high-school/6o4gkkc0j7csnteo2y26dr16y4dlcoidvg.png)
![6*(7-X) = (X+3)*5](https://img.qammunity.org/2020/formulas/mathematics/high-school/ab8j1hqbmnn9ktppxny5zufqji8x2t6ep2.png)
42-6X=5X+15
33=11X
X=3