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The lengths of two opposite sides of a square are decreased by 40\% while the lengths of the other two sides are increased by 50\% to form a rectangle. By what percent does the square's area decrease?

User Eyes
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5.9k points

2 Answers

2 votes

Answer:

10% decreased

Explanation:

The lengths of two opposite sides of a square are decreased by 40\% while the lengths-example-1
User AlienFromCA
by
5.6k points
3 votes

Answer:

The area has decreased a 10%.

Explanation:

Lets suppose that the the sides of the square are 1 cm, so the area is 1
cm^(2).

so if the square has been reduced 40% in widht, the new widht is 60% of what it was before. that means 0.6cm

then it was increased 50% on height, so the new height is 1.5 cm

The area of a rectangule is (height*widht)

A=(0.6*1.5)

A=0.9 [
cm^(2)]

The area of 0.9
cm^(2) represent the 90% of the first area, so the area was reduced a 10%. (100%-90%).

User Davide Consonni
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5.0k points