Question

The following reaction proceeds at a rate such that 3 mole of A is consumed per minute. Given this, how many moles of C are produced per minute? 2A+2B→4C Express your answer with the appropriate units.

Answer 1

For every mole of A consumed, two moles of C are produced. Given the consumption rate of 3 moles of A per minute, 6 moles of C are produced per minute.

Step-by-step explanation:

The mole ratio between reactant A and product C according to the balanced chemical equation 2A + 2B → 4C is 2:4, which simplifies to 1:2. Therefore, for every mole of A that is consumed, two moles of C are produced.In this reaction, 2 moles of A react with 2 moles of B to produce 4 moles of C. The stoichiometric ratio between A and C is 2:4 or 1:2. Since 3 moles of A are consumed per minute, we can calculate the moles of C produced per minute by using the stoichiometric ratio:

3 moles A → 3 moles A : 1.5 moles C : 4 moles C → 2 moles C

Therefore, 3 moles of A consumed per minute would produce 2 moles of C per minute. If 3 moles of A are consumed per minute, then the rate at which C is produced can be calculated by multiplying by the ratio of C to A, which is 2. Hence, 3 moles A/min * 2 moles C/mole A = 6 moles C/min.

Answer 2

6 moles of C are produced per minute

Step-by-step explanation:

According to law of mass action for the given reaction-

Rate =
`-(1)/(2)(\Delta [A])/(\Delta t)=-(1)/(2)(\Delta [B])/(\Delta t)=(1)/(4)(\Delta [c])/(\Delta t)`

Where
`-(\Delta [A])/(\Delta t)` represents rate of consumption of A and
`(\Delta [C])/(\Delta t)` represents rate of production of C

Here
`-(\Delta [A])/(\Delta t)` = 3 moles/min

So,
`(\Delta [C])/(\Delta t)` =
`(4)/(2)* -(\Delta [A])/(\Delta t)`

So,
`(\Delta [C])/(\Delta t)` =
`(4)/(2)* (3 moles/min)`

So,
`(\Delta [C])/(\Delta t)` = 6 moles/min