Question

Help me please! What is the equation of the line graphed below?

Answer 1

(0,-2) (-2, 3)

(3+2)/(-2-0)= -5/2

y + 2 = -5/2(x - 0)

y + 2 =( -5/2)x - 0

y = (-5/2)x - 2

Answer 2

y = -
`(5)/(2)` x - 2

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, - 2) and (x₂, y₂ ) = (- 2, 3) ← 2 points on the line

m =
`(3+2)/(-2-0)` = -
`(5)/(2)`

note the line crosses the y- axis at (0, - 2) ⇒ c = - 2

y = -
`(5)/(2)` x - 2 ← equation of line