Question

-25 Points-

A red die is tossed and then a green die is tossed. What is the probability that the red die shows a number larger than three and the green die shows a number less than three?

Answer 1

1/6

Explanation:

the probability of the red die shows a number larger than 3 (P1) = 3/6 = 1/2

the probability of the green die shows a number less than 3 (P2) = 2/6 = 1/3

the probability of both happening = P1 * P2 = (1/2) * (1/3) = 1/6

Answer 2

Assume that each of the 6 numbers has an equal probability of showing up for each die.

The probability of obtaining a six from the red die is 1/6, or

P(6 from the red die) = 1/6.

Similarly,

P(6 from the green die) = 1/6.

The tossing of the red die, followed by the tossing of the green die are independent events. Therefore

P(6 from the red die AND 6 from the green die) = (1/6)*(1/6) = 1/36.

Answer: 1/36