Question

The electron gun in a television tube is used to accelerate electrons with mass 9.109 × 10−31 kg from rest to 3 × 107 m/s within a distance of 6.3 cm. Assuming the electric field is constant, what electric field is required in the tube? The fundamental charge is qe .

Answer 1

To find the required electric field in the television tube, use the equation E = Δv/d, where Δv is the change in velocity and d is the distance.

Step-by-step explanation:

In order to find the electric field required in the television tube, we can use the equation:

E = Δv/d

where E is the electric field, Δv is the change in velocity (final velocity minus initial velocity), and d is the distance.

1. Calculate the change in velocity by subtracting the initial velocity (0 m/s) from the final velocity (3 × 10^7 m/s).
2. Convert the distance from centimeters to meters by dividing by 100.
3. Plug the values into the formula and calculate the electric field.

Answer 2

Electric field, E = 40608.75 N/C

Step-by-step explanation:

It is given that,

Mass of electrons,
`m=9.1* 10^(-31)\ kg`

Initial speed of electron, u = 0

Final speed of electrons,
`v=3* 10^7\ m/s`

Distance traveled, s = 6.3 cm = 0.063 m

Firstly, we will find the acceleration of the electron using third equation of motion as :

`a=(v^2-u^2)/(2s)`

`a=((3* 10^7)^2)/(2* 0.063)`

`a=7.14* 10^(15)\ m/s^2`

Now we will find the electric field required in the tube as :

`ma=qE`

`E=(ma)/(q)`

`E=(9.1* 10^(-31)* 7.14* 10^(15))/(1.6* 10^(-19))`

E = 40608.75 N/C

So, the electric field required in the tube is 40608.75 N/C. Hence, this is the required solution.