Question

Use your knowledge of the law of conservation of mass to answer the following question: From a laboratory process, a student collects 28.0 g of hydrogen and 224.0 g of oxygen. (Water -----> Hydrogen + Oxygen) How much water was originally involved in the process? (1 point)

Answer 1

`\boxed{\text{252.0 g}}`

Step-by-step explanation:

water ⟶ hydrogen + oxygen

mass/g: x 28.0 224.0

According to the Law of Conservation of Mass,

`\begin{array}{rcl}\\\text{Mass of reactants} & = & \text{mass of products} \\\text{Mass of water} & = & \text{mass of hydrogen + mass of oxygen} \\x & = & 28.0 + 224.0\\& = & \textbf{252.0 g}\\\end{array}\\\text{The mass of water was $\boxed{\textbf{252.0 g}}$}`