Question

If the nerve cell connecting the spinal cord to your feet is 1.4 m long, and the nerve impulse speed is 25 m/s, how many seconds does it take for the nerve signal to travel this distance?

Answer 1

Time taken by the nerve signal for travelling this distance
`= 0.056` seconds

Step-by-step explanation:

Given,

The length of nerve cell connecting the spinal cord to the feet
`= 1.4 m`

Speed of nerve impulse
`25(m)/(s)`

Time taken for the nerve signal to travel this distance is equal to the total " length of nerve cell connecting the spinal cord to the feet" divided by "speed of nerve impulse"

Substituting the given values in above equation, we get -

`(1.4)/(25)`

`= 0.056` seconds.

Thus , time taken by the nerve signal for travelling this distance
`= 0.056` seconds