Question

After landing, a jetliner on a straight runway taxis to a stop at an average velocity of If the plane takes 7.00 s to come to rest, what are the plane’s initial velocity and acceleration?

Answer 1

Plane's initial speed: 14
`(m)/(s)`

Plane's acceleration: -1
`(m)/(s^(2) )`

Step-by-step explanation:

average velocity =
`(V_(0) +V_f )/(2)`

V0=?

Vf= 0 m/s (rest)

t=7 s

Isolating V0

V0=2a-Vf = 2*(7) - 0= 14
`(m)/(s)`

Otherwise;

`a= (V_f-V_0)/(t) = (0(m)/(s)-7(m)/(s)  )/(7s) = <strong>-1 (m)/(s^2)`