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After landing, a jetliner on a straight runway taxis to a stop at an average velocity of If the plane takes 7.00 s to come to rest, what are the plane’s initial velocity and acceleration?

User Libbux
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1 Answer

5 votes

Answer:

Plane's initial speed: 14
(m)/(s)

Plane's acceleration: -1
(m)/(s^(2) )

Step-by-step explanation:

average velocity =
(V_(0) +V_f )/(2)

V0=?

Vf= 0 m/s (rest)

t=7 s

Isolating V0

V0=2a-Vf = 2*(7) - 0= 14
(m)/(s)

Otherwise;


a= (V_f-V_0)/(t) = (0(m)/(s)-7(m)/(s) &nbsp;)/(7s) = <strong>-1 (m)/(s^2)

User Mcha
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