Question

An object starts from rest at time t = 0.00 s and moves in the +x direction with constant acceleration. The object travels 14.0 m from time t = 1.00 s to time t = 2.00 s. What is the acceleration of the object?

Answer 1

28 m/s^2

Step-by-step explanation:

distance, s = 14 m

time, t = 2 - 1 = 1 s

initial velocity, u = 0 m/s

Let a be the acceleration.

Use third equation of motion

`s = ut + (1)/(2)at^(2)`

`14 = 0 + (1)/(2)a* 1^(2)`

a = 28 m/s^2

Thus, the acceleration is 28 m/s^2.