Question

Backpackers often use canisters of white gas to fuel a cooking stove's burner. If one canister contains 1.45 L of white gas, and the density of the gas is 0.710 g/cm3, how many kilograms of fuel are contained in one canister? Express the mass in kilograms to three significant figures.

Answer 1

Answer: One canister contains 1.03 Kg of fuel,

Step-by-step explanation:

The density is defined as the relation between the mass and the volume
`p=(m)/(v)`

First of all you need to have the same units for volume and density, so:

For the volume,

`1.45 L * (1.10*10^(-3)m^(3)  )/(1 L) = 1.45 *10^(-3) m^(3)`

For the density,

`p = 0.710(g)/(cm^(3) ) *(1cm^(3) )/(1*10^(-6)m^(3)  )*(1 Kg)/(1*10^(3)g ) = 710(Kg)/(m^(3) )`

From the density equation we have
`m=p*v`, so:

`710(Kg)/(m^(3) ) *1.45*10^(-3) m^(3) = 1.03Kg`