Answer:
19.613 N
0.10197 kg
Step-by-step explanation:
m = Mass of object = 2 kg
a = Acceleration due to gravity = 9.8065 m/s²
Force
![F=m(GM)/(r^2)\\\F=ma](https://img.qammunity.org/2020/formulas/engineering/college/l093ffp01wv35cudqr0nae83vi1mfzd5m2.png)
where
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
M = Mass of Earth = 5.972 × 10²⁴ kg
r = Radius of Earth = 6.3781×10⁶ m
⇒F = ma
⇒F = 2×9.8065
⇒F = 19.613 N
∴ Force needed to hold a mass at rest is 19.613 N.
Force = F = 1 N
F = ma
![1=m9.8065\\\Rightarrow m=(1)/(9.8065)\\\Rightarrow m=0.10197\ kg](https://img.qammunity.org/2020/formulas/engineering/college/eb0myoa445swf5s7sy8vqlopad6odc1lwq.png)
∴ 1 N can support 0.10197 kg of mass