Question

For the following reaction, 5.21 grams of nitrogen gas are allowed to react with 5.91 grams of hydrogen gas.

nitrogen (g) + hydrogen (g) → ammonia (g)

What is the maximum amount of ammonia that can be formed?

Answer 1

Maximum amount of ammonia that can be formed is 6.32 g

Step-by-step explanation:

The balanced equation is:

N2 + 3H2\rightarrow 2NH3

`Moles\ N2 = (5.21g)/(28g/mol) =0.186\\\\Moles H2 = (5.21g)/(2g/mol) =2.61`

N2 is the limiting reactant

Based on the reaction stoichiometry:

1 mole N2 produced 2 moles NH3

therefore, 0.186 mol N2 will yield: 2(0.186) = 0.372 moles NH3

Molar mass NH3 = 17 g/mol

`Maximum\ Mass\ NH3 = 0.372 mols*17g/mol=6.32g`