Question

Two forces are acting on an object. Force 1 on the object is 6.0 N and to the right at zero degrees. Force 2 on the object is 8.0 N upwards, or 90 degrees. At what angle should a force be applied that perfectly balances the forces acting on the object?

Answer 1

233.12 deg

Step-by-step explanation:

`F_(1)` = Force acting on the object in right direction = 6.0 N

`F_(2)` = Force acting on the object in upward direction = 8.0 N
`\theta` = Angle made by the resultant force relative to right direction

From the diagram , Angle made by the resultant force relative to right direction is given as

`\theta = tan^(-1)\left ( (F_(2))/(F_(1)) \right )`

`\theta = tan^(-1)\left ( (8)/(6) \right )`

`\theta = 53.12` deg

`\phi` = Angle of equilibrium force relative to the right direction

From the diagram, Angle of equilibrium force relative to the right direction is given as

`\phi = \theta  + 180`

`\phi = 53.12  + 180`

`\phi = 233.12` deg