Question

Number 12. Find angle ADE

Answer 1

Angle ADE = 59 degrees
(4x+15)+(13x+7)=90degrees
17x+22=90degrees
68=17x
4=x
Angle DBC= 59 degrees
Angle DCB = 90degrees
Triangle = 180degrees
90+59=149
180-149=31 degrees
Angle EDC = 31
90-31=59 degrees
Angle ADE = 59 degrees

Answer 2

ADE=59º

Explanation:

4x+15+13x+7=90

17x+22=90

17x=68

x=4

angle B=angle ADE so we plug in x=4 into 13x+7

13(4)+7=59º