Question

If​ f(x) is defined as​ follows,

f(x) = 16x^2 + 4x + 64
find​
(a) f(-2)
(b) f(0)
(c) f(1)

Answer 1

Answer: The required values are

f(-2) = 120, f(0) = 64 and f(1) = 84.

Step-by-step explanation: We are given the following function f(x) :

`f(x)=16x^2+4x+64~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)`

We are to find the values of the following :

`(a)~f(-2),\\\\(b)~f(0),\\\\(c)~f(1).`

To find the values of the function at the given points, we need to substitute the corresponding values of x in equation (i).

Substituting x = -2 in equation (i), we get

`f(-2)=16*(-2)^2+4*(-2)+64=64-8+64=120.`

Substituting x = 0 in equation (i), we get

`f(0)=16*0^2+4*0+64=0+0+64=64.`

Substituting x = 1 in equation (i), we get

`f(1)=16*1^2+4*1+64=16+4+64=84.`

Thus, the required values are

f(-2) = 120, f(0) = 64 and f(1) = 84.