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Sam and Janet each have a whole number of dollars, and 13$ of Sam's money equals 2$ of Janet's money. Together, they have more than 10$. What is the least number of dollars they could have combined?

User Nosferat
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Answer:

The least sum they could have is 15 dollars (n=1).

Step-by-step explanation:

Let S and J represent the number of dollars held by Sam and Janet, respectively. Let

.. n = S/13 = J/2

Then

.. S = 13n

.. J = 2n

.. S + J = 13n +2n = 15n > 10 . . . . .

we know that from question, the sum of their amount is more than $10

therefore, The least sum they could have is 15 dollars (n=1).

User Goranek
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