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Given the differential equation x′=−(x+3)(x+1)3(x−1)2(x−2.5). List the constant (i.e. equilibrium) solutions to this differential equation in increasing order and indicate whether or not these solutions are stable, semi-stable, or unstable.

User Harsha
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Answer:


X_(1)=-3 Stable


X_(2)=-1 Instable


X_(3)=1 Semistable


X_(4)=2.5 Instable

Explanation:

Equilibrium constant solutions (or critical points) occur whenever x′ = f(x) = 0

x′=−(x+3)(x+1)3(x−1)2(x−2.5)=0


X_(1)=-3


X_(2)=-1


X_(3)=1


X_(4)=2.5

we can see the plot of x′ = f(x) in the figure annexed. In order to analyse the stability of the constant solutions, we must see how the function changes around the constant solutions X's:

(i.) If f(x) < 0 on the left of X, and f(y) > 0 on the right of

X, then the equilibrium solution is unstable.

(ii.) If f(X) > 0 on the left of X, and f(y) < 0 on the right of

X, then the equilibrium solution y = c is stable.

(iii.) If f(x) > 0 on both sides of X, or f(x) < 0 on both

sides of c, then the equilibrium solution y = X is

semistable.

Then:


X_(1)=-3 Stable


X_(2)=-1 Instable


X_(3)=1 Semistable


X_(4)=2.5 Instable

Given the differential equation x′=−(x+3)(x+1)3(x−1)2(x−2.5). List the constant (i-example-1
User Eduardo Herzer
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