Answer:
=-3 Stable
=-1 Instable
=1 Semistable
=2.5 Instable
Explanation:
Equilibrium constant solutions (or critical points) occur whenever x′ = f(x) = 0
x′=−(x+3)(x+1)3(x−1)2(x−2.5)=0
=-3
=-1
=1
=2.5
we can see the plot of x′ = f(x) in the figure annexed. In order to analyse the stability of the constant solutions, we must see how the function changes around the constant solutions X's:
(i.) If f(x) < 0 on the left of X, and f(y) > 0 on the right of
X, then the equilibrium solution is unstable.
(ii.) If f(X) > 0 on the left of X, and f(y) < 0 on the right of
X, then the equilibrium solution y = c is stable.
(iii.) If f(x) > 0 on both sides of X, or f(x) < 0 on both
sides of c, then the equilibrium solution y = X is
semistable.
Then:
=-3 Stable
=-1 Instable
=1 Semistable
=2.5 Instable