Answer:
correct option is B i.e. 155 m
Step-by-step explanation:
by equation of motion we have
v^2 = u^2 + 2as
where
u is initial velocity = 30 m/s
v is descending velocity = 20 m/s
a is acceleration due to gravity = 1.62 m/s^2
s is height of rock
so we have height at descending is
20^2 = 30^2 - 2*1.62*s
s = 154.32 m
so correct option is B