Answer:
Total 18 task force can be formed.
Explanation:
Total number of men = 4
Total number of women = 3
We need to form a 4-person task force.
The total number of ways of selecting r items from n items is
![^nC_r=(n!)/(r!(n-r)!)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/keq9fu1kexw4i9m71wsvnyit4wbq0pynjj.png)
Total number of ways of selecting 2 men from 4 men =
![^4C_2](https://img.qammunity.org/2020/formulas/mathematics/high-school/q721zdmodvpcrjeo2qmxfal2n0vfz7qub1.png)
Total number of ways of selecting 2 women from 3 men =
![^3C_2](https://img.qammunity.org/2020/formulas/mathematics/high-school/be4pmg8g0c7a238kvsnpgrbtccla9a3qyw.png)
Total number of different task forces that can be formed is
![Total=^4C_2* ^3C_2](https://img.qammunity.org/2020/formulas/mathematics/high-school/ley3e6yx4te8qz9qvb0mlbpwx7x46iolow.png)
![Total=(4!)/(2!(4-2)!)* (3!)/(2!(3-2)!)](https://img.qammunity.org/2020/formulas/mathematics/high-school/upkfy0dsru4koyzvuq4g56blhrux8cds51.png)
![Total=(4!)/(2!2!)* (3!)/(2!1!)](https://img.qammunity.org/2020/formulas/mathematics/high-school/vmus6jlotc4encls5s6gbyorex6pkub77y.png)
![Total=(4* 3* 2!)/(2* 1* 2!)* (3\tmes 2!)/(2!)](https://img.qammunity.org/2020/formulas/mathematics/high-school/pbz2liipdtgqq1epwfv0kmav64zwqvql3r.png)
Cancel out common factors.
![Total=6* 3](https://img.qammunity.org/2020/formulas/mathematics/high-school/qvl2ufcpr032eksy99dtwhpl51bcjixeja.png)
![Total=18](https://img.qammunity.org/2020/formulas/mathematics/high-school/o3kqsbq0952ku615iwuwd5bbra3nosx78d.png)
Therefore total 18 task force can be formed.